# 12 coins balance problem

Hi,
today, in this short post I want to show you this cool puzzle that I first encountered on my summer camp. The problem goes like this:

You have got 12 coins. One of them may be false one. You can not know by looking but you have a balance weights. You are allowed to use it 3 times and find out which one of the coins is heavier or lighter (you do not know and it might happen that none is).

I really recommend you to try it out. I almost had a solution though when I checked it I saw that I had mistake in one of the scenarios. Try it out for yourself and in next post I will reveal the solution.

Dragallur

HINT BELOW:

Try to take first step of weighting 4 coins against 4 coins, it will help you 😉

## 4 thoughts on “12 coins balance problem”

1. OK, I’m going to give this a go. (don’t laugh)

Time 1: If you weigh 4 against 4 & it comes out even, then you’ve only the remaining 4. If it comes out uneven, then you’ve got the lighter 4.
Time 2: 2 against 2. Take out the lighter 2 for the next weigh
Time 3: 1 against 1 from the previous weigh. Lighter one is false.

How off base am I?

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• The problem is that you do not know if the coin is lighter or not which means that if in the first Time it comes out uneven you do not know if the “heavier part” has heavier coin or the lighter part lighter coin and vica versa. This makes it way more complicated. But thanks for trying! You still have time to get to the right solution before I post the answer (probably tommorow because today I was busy with some other stuff) 😉

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• NNNNNOOOOOOO!!!! Duh, I just assumed the faux coin would be lighter. Back to the drawing board, I guess.

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